I guess there is some kinds of group structure for the splitter matrix, could be an isomorphism to 2-body exchange group ? I guess there are somethings interesting for a ring-setting, for example, for 4-belts. To investigate this problem more, lets study the algebra for the splitter matrix. But we haven’t find a finite splitters setting for mixing 3 loads. Following this idea, the 2^n belts can be done.įor 6-belts, we can separate them into 3 pairs, and mix the 3 pairs. next, mix the 2-3 belts, and 1-4 belts will do the job. The idea behind is, first mixing the 1-2 belts, the 3-4 belts, at this point the loads of 1-2 are the same and that for 3-4 are the same too. The matrix has the matrix element to be 1/4, exactly!! In the community of factorio player, they found this setting long time ago. The last splitter connect the 1st belt and the 4-belt. How about for finite splitters? For 4-belts, lets try this setting It turns out is yes, for an infinite block, we can evenly distribute the load. Good enough.Ĭan we using a similar idea to bull-force the problem for 4-belts, or n-belts in general? In practice, 3 pairs of splitters, setting the input load vector be, the output load vector is. Thus, in principle, we need infinity block to evenly distribute the loading for 3 belts. We can see that,, the matrix element goes to 1/3. Lets try to use this black for k-times, but before that, to compute power of matrix, it is better to diagonalize the matrix, The splitter matrix isįor example, we have 3 belts, and if we want to evenly distribute among them, we try putting 2 splitters like this.Ĭlearly, it is far from a evenly distributed matrix, that all element are. If we have n-belts, a splitter is placed between the i-th and j-th belt. Since the total number of load must be the same before and after a splitter, thus, the sum of the element in each row must be 1 for a splitter matrix. If we define the load as a vector, the splitter is a matrix that transform the load vector. Suppose we have 2-belts-in and 2-belts-out, we can place a splitter in the middle. To solve the problem, lets look at the mathematics for a splitter. There is also a splitter, that can divide the belt into 2 belts and distribute the load evenly.Ī problem is, suppose we have n-belts and different load, how can we use splitters to evenly distribute the load into m-belts? For massive transport, 2 or more belts will be used in parallel. Inside, the transport belt is the main way to transport materials from one place to another place.
0 Comments
Leave a Reply. |
AuthorWrite something about yourself. No need to be fancy, just an overview. ArchivesCategories |